Base | Representation |
---|---|
bin | 10111001010110011… |
… | …01001100100100011 |
3 | 1012002212111102120212 |
4 | 23211121221210203 |
5 | 200433243002211 |
6 | 5414135124335 |
7 | 620145463163 |
oct | 134531514443 |
9 | 35085442525 |
10 | 12438640931 |
11 | 530331a042 |
12 | 24b18136ab |
13 | 1232cb5182 |
14 | 85dda05a3 |
15 | 4cc01838b |
hex | 2e5669923 |
12438640931 has 2 divisors, whose sum is σ = 12438640932. Its totient is φ = 12438640930.
The previous prime is 12438640901. The next prime is 12438640933. The reversal of 12438640931 is 13904683421.
12438640931 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12438640931 - 222 = 12434446627 is a prime.
It is a super-2 number, since 2×124386409312 (a number of 21 digits) contains 22 as substring.
Together with 12438640933, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12438640933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6219320465 + 6219320466.
It is an arithmetic number, because the mean of its divisors is an integer number (6219320466).
Almost surely, 212438640931 is an apocalyptic number.
12438640931 is a deficient number, since it is larger than the sum of its proper divisors (1).
12438640931 is an equidigital number, since it uses as much as digits as its factorization.
12438640931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 12438640931 in words is "twelve billion, four hundred thirty-eight million, six hundred forty thousand, nine hundred thirty-one".
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