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124400032013 is a prime number
BaseRepresentation
bin111001111011011010…
…0011101100100001101
3102220002122121101201002
41303312310131210031
54014232402011023
6133052032230045
711662514553035
oct1636664354415
9386078541632
10124400032013
1148837636314
122013939b325
13b96695baca
14604186c8c5
1533813e8b28
hex1cf6d1d90d

124400032013 has 2 divisors, whose sum is σ = 124400032014. Its totient is φ = 124400032012.

The previous prime is 124400031979. The next prime is 124400032019. The reversal of 124400032013 is 310230004421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93389526409 + 31010505604 = 305597^2 + 176098^2 .

It is an emirp because it is prime and its reverse (310230004421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 124400032013 - 28 = 124400031757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124400032019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62200016006 + 62200016007.

It is an arithmetic number, because the mean of its divisors is an integer number (62200016007).

Almost surely, 2124400032013 is an apocalyptic number.

It is an amenable number.

124400032013 is a deficient number, since it is larger than the sum of its proper divisors (1).

124400032013 is an equidigital number, since it uses as much as digits as its factorization.

124400032013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 124400032013 its reverse (310230004421), we get a palindrome (434630036434).

The spelling of 124400032013 in words is "one hundred twenty-four billion, four hundred million, thirty-two thousand, thirteen".