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12440403111217 is a prime number
BaseRepresentation
bin1011010100001000000111…
…0011101110110100110001
31122001021212002020011220211
42311002001303232310301
53112310421144024332
642243013045104121
72422534533464464
oct265020163566461
948037762204824
1012440403111217
113a66a44265704
12148b0499b8041
136c3181770c13
14310193ac32db
1516890b8cb447
hexb5081ceed31

12440403111217 has 2 divisors, whose sum is σ = 12440403111218. Its totient is φ = 12440403111216.

The previous prime is 12440403111211. The next prime is 12440403111281. The reversal of 12440403111217 is 71211130404421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6482976576561 + 5957426534656 = 2546169^2 + 2440784^2 .

It is a cyclic number.

It is not a de Polignac number, because 12440403111217 - 23 = 12440403111209 is a prime.

It is a super-3 number, since 3×124404031112173 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12440403111211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220201555608 + 6220201555609.

It is an arithmetic number, because the mean of its divisors is an integer number (6220201555609).

Almost surely, 212440403111217 is an apocalyptic number.

It is an amenable number.

12440403111217 is a deficient number, since it is larger than the sum of its proper divisors (1).

12440403111217 is an equidigital number, since it uses as much as digits as its factorization.

12440403111217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 31.

Adding to 12440403111217 its reverse (71211130404421), we get a palindrome (83651533515638).

The spelling of 12440403111217 in words is "twelve trillion, four hundred forty billion, four hundred three million, one hundred eleven thousand, two hundred seventeen".