Base | Representation |
---|---|
bin | 1011010100001000000111… |
… | …0011101110110100101011 |
3 | 1122001021212002020011220121 |
4 | 2311002001303232310223 |
5 | 3112310421144024321 |
6 | 42243013045104111 |
7 | 2422534533464455 |
oct | 265020163566453 |
9 | 48037762204817 |
10 | 12440403111211 |
11 | 3a66a442656a9 |
12 | 148b0499b8037 |
13 | 6c3181770c0a |
14 | 310193ac32d5 |
15 | 16890b8cb441 |
hex | b5081ceed2b |
12440403111211 has 2 divisors, whose sum is σ = 12440403111212. Its totient is φ = 12440403111210.
The previous prime is 12440403111209. The next prime is 12440403111217. The reversal of 12440403111211 is 11211130404421.
12440403111211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12440403111211 - 21 = 12440403111209 is a prime.
Together with 12440403111209, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12440403111217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220201555605 + 6220201555606.
It is an arithmetic number, because the mean of its divisors is an integer number (6220201555606).
Almost surely, 212440403111211 is an apocalyptic number.
12440403111211 is a deficient number, since it is larger than the sum of its proper divisors (1).
12440403111211 is an equidigital number, since it uses as much as digits as its factorization.
12440403111211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 12440403111211 its reverse (11211130404421), we get a palindrome (23651533515632).
The spelling of 12440403111211 in words is "twelve trillion, four hundred forty billion, four hundred three million, one hundred eleven thousand, two hundred eleven".
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