Base | Representation |
---|---|
bin | 10111001011000000… |
… | …11110101000010001 |
3 | 1012002222212101021012 |
4 | 23211200132220101 |
5 | 200434222243441 |
6 | 5414241340305 |
7 | 620166630326 |
oct | 134540365021 |
9 | 35088771235 |
10 | 12440431121 |
11 | 5304332038 |
12 | 24b2337695 |
13 | 1233490c61 |
14 | 860308b4d |
15 | 4cc26d9eb |
hex | 2e581ea11 |
12440431121 has 2 divisors, whose sum is σ = 12440431122. Its totient is φ = 12440431120.
The previous prime is 12440431103. The next prime is 12440431123. The reversal of 12440431121 is 12113404421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6550636096 + 5889795025 = 80936^2 + 76745^2 .
It is a cyclic number.
It is not a de Polignac number, because 12440431121 - 222 = 12436236817 is a prime.
Together with 12440431123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12440431123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220215560 + 6220215561.
It is an arithmetic number, because the mean of its divisors is an integer number (6220215561).
Almost surely, 212440431121 is an apocalyptic number.
It is an amenable number.
12440431121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12440431121 is an equidigital number, since it uses as much as digits as its factorization.
12440431121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12440431121 its reverse (12113404421), we get a palindrome (24553835542).
The spelling of 12440431121 in words is "twelve billion, four hundred forty million, four hundred thirty-one thousand, one hundred twenty-one".
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