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1244058625993 is a prime number
BaseRepresentation
bin10010000110100111101…
…011000010011111001001
311101221010120210012200011
4102012213223002133021
5130340313002012433
62351302421511521
7155610634562461
oct22064753023711
94357116705604
101244058625993
1143a669730997
121811348725a1
13904114773c1
14442d9b4aba1
1522562b783cd
hex121a7ac27c9

1244058625993 has 2 divisors, whose sum is σ = 1244058625994. Its totient is φ = 1244058625992.

The previous prime is 1244058625973. The next prime is 1244058626021. The reversal of 1244058625993 is 3995268504421.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 927143671689 + 316914954304 = 962883^2 + 562952^2 .

It is an emirp because it is prime and its reverse (3995268504421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1244058625993 - 213 = 1244058617801 is a prime.

It is not a weakly prime, because it can be changed into another prime (1244058625973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622029312996 + 622029312997.

It is an arithmetic number, because the mean of its divisors is an integer number (622029312997).

Almost surely, 21244058625993 is an apocalyptic number.

It is an amenable number.

1244058625993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1244058625993 is an equidigital number, since it uses as much as digits as its factorization.

1244058625993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18662400, while the sum is 58.

The spelling of 1244058625993 in words is "one trillion, two hundred forty-four billion, fifty-eight million, six hundred twenty-five thousand, nine hundred ninety-three".