Search a number
-
+
124411004114093 is a prime number
BaseRepresentation
bin11100010010011010110001…
…101101001101010010101101
3121022111120112210020000120122
4130102122301231031102231
5112301322214023122333
61120333343135254325
735130253442420504
oct3422326155152255
9538446483200518
10124411004114093
1136706457485a44
1211b5382967a3a5
135455ba459b848
1422a174bbd383b
15e5b33810c798
hex7126b1b4d4ad

124411004114093 has 2 divisors, whose sum is σ = 124411004114094. Its totient is φ = 124411004114092.

The previous prime is 124411004114077. The next prime is 124411004114119. The reversal of 124411004114093 is 390411400114421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109775344981129 + 14635659132964 = 10477373^2 + 3825658^2 .

It is a cyclic number.

It is not a de Polignac number, because 124411004114093 - 24 = 124411004114077 is a prime.

It is a super-2 number, since 2×1244110041140932 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124411004114003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62205502057046 + 62205502057047.

It is an arithmetic number, because the mean of its divisors is an integer number (62205502057047).

Almost surely, 2124411004114093 is an apocalyptic number.

It is an amenable number.

124411004114093 is a deficient number, since it is larger than the sum of its proper divisors (1).

124411004114093 is an equidigital number, since it uses as much as digits as its factorization.

124411004114093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 124411004114093 in words is "one hundred twenty-four trillion, four hundred eleven billion, four million, one hundred fourteen thousand, ninety-three".