Base | Representation |
---|---|
bin | 1011010100001110001011… |
… | …1110111111110101001101 |
3 | 1122001110001201000012100011 |
4 | 2311003202332333311031 |
5 | 3112322241031020123 |
6 | 42243442525033221 |
7 | 2422623121252603 |
oct | 265034276776515 |
9 | 48043051005304 |
10 | 12442033454413 |
11 | 3a67700581682 |
12 | 148b4239b5811 |
13 | 6c338146bc34 |
14 | 3102aa435873 |
15 | 1689a4ac0e0d |
hex | b50e2fbfd4d |
12442033454413 has 2 divisors, whose sum is σ = 12442033454414. Its totient is φ = 12442033454412.
The previous prime is 12442033454377. The next prime is 12442033454443. The reversal of 12442033454413 is 31445433024421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12412783219684 + 29250234729 = 3523178^2 + 171027^2 .
It is a cyclic number.
It is not a de Polignac number, because 12442033454413 - 213 = 12442033446221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12442033454443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6221016727206 + 6221016727207.
It is an arithmetic number, because the mean of its divisors is an integer number (6221016727207).
Almost surely, 212442033454413 is an apocalyptic number.
It is an amenable number.
12442033454413 is a deficient number, since it is larger than the sum of its proper divisors (1).
12442033454413 is an equidigital number, since it uses as much as digits as its factorization.
12442033454413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 12442033454413 its reverse (31445433024421), we get a palindrome (43887466478834).
The spelling of 12442033454413 in words is "twelve trillion, four hundred forty-two billion, thirty-three million, four hundred fifty-four thousand, four hundred thirteen".
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