Base | Representation |
---|---|
bin | 10111001011010000… |
… | …11011000001011111 |
3 | 1012010010210011202110 |
4 | 23211220123001133 |
5 | 200440240413003 |
6 | 5414354125103 |
7 | 620223422400 |
oct | 134550330137 |
9 | 35103704673 |
10 | 12442513503 |
11 | 5305524612 |
12 | 24b2b80793 |
13 | 1233a3ca34 |
14 | 8606cb9a7 |
15 | 4cc530a03 |
hex | 2e5a1b05f |
12442513503 has 48 divisors (see below), whose sum is σ = 20636537184. Its totient is φ = 6625382400.
The previous prime is 12442513487. The next prime is 12442513541. The reversal of 12442513503 is 30531524421.
It is not a de Polignac number, because 12442513503 - 24 = 12442513487 is a prime.
It is a super-3 number, since 3×124425135033 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12442513553) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 227751 + ... + 277047.
It is an arithmetic number, because the mean of its divisors is an integer number (429927858).
Almost surely, 212442513503 is an apocalyptic number.
12442513503 is a deficient number, since it is larger than the sum of its proper divisors (8194023681).
12442513503 is a wasteful number, since it uses less digits than its factorization.
12442513503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49432 (or 49425 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
The spelling of 12442513503 in words is "twelve billion, four hundred forty-two million, five hundred thirteen thousand, five hundred three".
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