Base | Representation |
---|---|
bin | 1011010100010011010010… |
… | …0011111101111010111111 |
3 | 1122001120121002100121200211 |
4 | 2311010310203331322333 |
5 | 3112333041414203130 |
6 | 42244230415533251 |
7 | 2423002050460306 |
oct | 265046443757277 |
9 | 48046532317624 |
10 | 12443402100415 |
11 | 3a682430a5680 |
12 | 148b74622a227 |
13 | 6c353bb90340 |
14 | 31039a10543d |
15 | 168a34d20a2a |
hex | b51348fdebf |
12443402100415 has 32 divisors (see below), whose sum is σ = 17548644810816. Its totient is φ = 8350727669760.
The previous prime is 12443402100391. The next prime is 12443402100419. The reversal of 12443402100415 is 51400120434421.
It is a happy number.
It is not a de Polignac number, because 12443402100415 - 215 = 12443402067647 is a prime.
It is a super-2 number, since 2×124434021004152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12443402100419) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 932332 + ... + 5075041.
It is an arithmetic number, because the mean of its divisors is an integer number (548395150338).
Almost surely, 212443402100415 is an apocalyptic number.
12443402100415 is a deficient number, since it is larger than the sum of its proper divisors (5105242710401).
12443402100415 is a wasteful number, since it uses less digits than its factorization.
12443402100415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6010299.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 12443402100415 its reverse (51400120434421), we get a palindrome (63843522534836).
The spelling of 12443402100415 in words is "twelve trillion, four hundred forty-three billion, four hundred two million, one hundred thousand, four hundred fifteen".
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