12443403320041 has 2 divisors, whose sum is σ = 12443403320042. Its totient is φ = 12443403320040.

The previous prime is 12443403320039. The next prime is 12443403320099. The reversal of 12443403320041 is 14002330434421.

12443403320041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9775502496400 + 2667900823641 = 3126580^2 + 1633371^2 .

It is a cyclic number.

It is not a de Polignac number, because 12443403320041 - 2¹ = 12443403320039 is a prime.

Together with 12443403320039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12443403319985 and 12443403320012.

It is not a weakly prime, because it can be changed into another prime (12443403320941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6221701660020 + 6221701660021.

It is an arithmetic number, because the mean of its divisors is an integer number (6221701660021).

Almost surely, 2^{12443403320041} is an apocalyptic number.

It is an amenable number.

12443403320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12443403320041 is an equidigital number, since it uses as much as digits as its factorization.

12443403320041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 12443403320041 its reverse (14002330434421), we get a palindrome (26445733754462).

The spelling of 12443403320041 in words is "twelve trillion, four hundred forty-three billion, four hundred three million, three hundred twenty thousand, forty-one".