Base | Representation |
---|---|
bin | 10010000110111100111… |
… | …000010011000110101111 |
3 | 11101222001101021121001112 |
4 | 102012330320103012233 |
5 | 130342030043022341 |
6 | 2351402011502235 |
7 | 155622515034062 |
oct | 22067470230657 |
9 | 4358041247045 |
10 | 1244414423471 |
11 | 43a83155589a |
12 | 181213a5797b |
13 | 9046a0b035b |
14 | 443310c68d9 |
15 | 22584009aeb |
hex | 121bce131af |
1244414423471 has 2 divisors, whose sum is σ = 1244414423472. Its totient is φ = 1244414423470.
The previous prime is 1244414423353. The next prime is 1244414423489. The reversal of 1244414423471 is 1743244144421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1244414423471 - 238 = 969536516527 is a prime.
It is a super-3 number, since 3×12444144234713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1244414428471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622207211735 + 622207211736.
It is an arithmetic number, because the mean of its divisors is an integer number (622207211736).
Almost surely, 21244414423471 is an apocalyptic number.
1244414423471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244414423471 is an equidigital number, since it uses as much as digits as its factorization.
1244414423471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 344064, while the sum is 41.
Adding to 1244414423471 its reverse (1743244144421), we get a palindrome (2987658567892).
The spelling of 1244414423471 in words is "one trillion, two hundred forty-four billion, four hundred fourteen million, four hundred twenty-three thousand, four hundred seventy-one".
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