Base | Representation |
---|---|
bin | 111001111110101101… |
… | …1110100010100110011 |
3 | 102220101101102202211102 |
4 | 1303331123310110303 |
5 | 4014444304342042 |
6 | 133111035035015 |
7 | 11665333066214 |
oct | 1637533642463 |
9 | 386341382742 |
10 | 124511012147 |
11 | 48894247335 |
12 | 2016a59ba6b |
13 | b983948322 |
14 | 60524bb40b |
15 | 338b01bb32 |
hex | 1cfd6f4533 |
124511012147 has 2 divisors, whose sum is σ = 124511012148. Its totient is φ = 124511012146.
The previous prime is 124511012123. The next prime is 124511012149. The reversal of 124511012147 is 741210115421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124511012147 - 212 = 124511008051 is a prime.
Together with 124511012149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (124511012149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62255506073 + 62255506074.
It is an arithmetic number, because the mean of its divisors is an integer number (62255506074).
Almost surely, 2124511012147 is an apocalyptic number.
124511012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
124511012147 is an equidigital number, since it uses as much as digits as its factorization.
124511012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2240, while the sum is 29.
Adding to 124511012147 its reverse (741210115421), we get a palindrome (865721127568).
The spelling of 124511012147 in words is "one hundred twenty-four billion, five hundred eleven million, twelve thousand, one hundred forty-seven".
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