Search a number
-
+
124511012147 is a prime number
BaseRepresentation
bin111001111110101101…
…1110100010100110011
3102220101101102202211102
41303331123310110303
54014444304342042
6133111035035015
711665333066214
oct1637533642463
9386341382742
10124511012147
1148894247335
122016a59ba6b
13b983948322
1460524bb40b
15338b01bb32
hex1cfd6f4533

124511012147 has 2 divisors, whose sum is σ = 124511012148. Its totient is φ = 124511012146.

The previous prime is 124511012123. The next prime is 124511012149. The reversal of 124511012147 is 741210115421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 124511012147 - 212 = 124511008051 is a prime.

Together with 124511012149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (124511012149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62255506073 + 62255506074.

It is an arithmetic number, because the mean of its divisors is an integer number (62255506074).

Almost surely, 2124511012147 is an apocalyptic number.

124511012147 is a deficient number, since it is larger than the sum of its proper divisors (1).

124511012147 is an equidigital number, since it uses as much as digits as its factorization.

124511012147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2240, while the sum is 29.

Adding to 124511012147 its reverse (741210115421), we get a palindrome (865721127568).

The spelling of 124511012147 in words is "one hundred twenty-four billion, five hundred eleven million, twelve thousand, one hundred forty-seven".