Base | Representation |
---|---|
bin | 10010000111110100101… |
… | …010110001010111111011 |
3 | 11102001110121111012120121 |
4 | 102013310222301113323 |
5 | 130400434200322111 |
6 | 2352034525034111 |
7 | 155654641520065 |
oct | 22076452612773 |
9 | 4361417435517 |
10 | 1245350401531 |
11 | 440171920a85 |
12 | 1814353b5937 |
13 | 90588c92a22 |
14 | 443bd52a735 |
15 | 225db291871 |
hex | 121f4ab15fb |
1245350401531 has 2 divisors, whose sum is σ = 1245350401532. Its totient is φ = 1245350401530.
The previous prime is 1245350401489. The next prime is 1245350401553. The reversal of 1245350401531 is 1351040535421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1245350401531 - 211 = 1245350399483 is a prime.
It is a super-2 number, since 2×12453504015312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1245350401231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622675200765 + 622675200766.
It is an arithmetic number, because the mean of its divisors is an integer number (622675200766).
Almost surely, 21245350401531 is an apocalyptic number.
1245350401531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1245350401531 is an equidigital number, since it uses as much as digits as its factorization.
1245350401531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 1245350401531 its reverse (1351040535421), we get a palindrome (2596390936952).
The spelling of 1245350401531 in words is "one trillion, two hundred forty-five billion, three hundred fifty million, four hundred one thousand, five hundred thirty-one".
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