Base | Representation |
---|---|
bin | 1011010101000000011011… |
… | …1011100011011000101101 |
3 | 1122002201212201000111202120 |
4 | 2311100012323203120231 |
5 | 3113032401441330013 |
6 | 42253553151143153 |
7 | 2423611301215662 |
oct | 265200673433055 |
9 | 48081781014676 |
10 | 12455521433133 |
11 | 3a723a2152729 |
12 | 1491b68b14ab9 |
13 | 6c472097712c |
14 | 310bc9907a69 |
15 | 168ee3cb4123 |
hex | b5406ee362d |
12455521433133 has 64 divisors (see below), whose sum is σ = 17711225551872. Its totient is φ = 7775543393280.
The previous prime is 12455521433111. The next prime is 12455521433177. The reversal of 12455521433133 is 33133412555421.
12455521433133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12455521433133 - 29 = 12455521432621 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12455521434133) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 131655435 + ... + 131750007.
It is an arithmetic number, because the mean of its divisors is an integer number (276737899248).
Almost surely, 212455521433133 is an apocalyptic number.
It is an amenable number.
12455521433133 is a deficient number, since it is larger than the sum of its proper divisors (5255704118739).
12455521433133 is a wasteful number, since it uses less digits than its factorization.
12455521433133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95094.
The product of its digits is 648000, while the sum is 42.
Adding to 12455521433133 its reverse (33133412555421), we get a palindrome (45588933988554).
The spelling of 12455521433133 in words is "twelve trillion, four hundred fifty-five billion, five hundred twenty-one million, four hundred thirty-three thousand, one hundred thirty-three".
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