Base | Representation |
---|---|
bin | 111010000101101011… |
… | …0001110111110001111 |
3 | 102220222122122121011220 |
4 | 1310023112032332033 |
5 | 4020434033220310 |
6 | 133150134014423 |
7 | 12004166104152 |
oct | 1641326167617 |
9 | 386878577156 |
10 | 124744429455 |
11 | 489a3a841a8 |
12 | 202147a7413 |
13 | b9c0102b89 |
14 | 60754bbc99 |
15 | 33a1777670 |
hex | 1d0b58ef8f |
124744429455 has 32 divisors (see below), whose sum is σ = 211373924544. Its totient is φ = 62604312576.
The previous prime is 124744429441. The next prime is 124744429487. The reversal of 124744429455 is 554924447421.
It is not a de Polignac number, because 124744429455 - 29 = 124744428943 is a prime.
It is a super-2 number, since 2×1247444294552 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a junction number, because it is equal to n+sod(n) for n = 124744429398 and 124744429407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1304559 + ... + 1396911.
It is an arithmetic number, because the mean of its divisors is an integer number (6605435142).
Almost surely, 2124744429455 is an apocalyptic number.
124744429455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
124744429455 is a deficient number, since it is larger than the sum of its proper divisors (86629495089).
124744429455 is a wasteful number, since it uses less digits than its factorization.
124744429455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97675.
The product of its digits is 6451200, while the sum is 51.
The spelling of 124744429455 in words is "one hundred twenty-four billion, seven hundred forty-four million, four hundred twenty-nine thousand, four hundred fifty-five".
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