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1247483113 is a prime number
BaseRepresentation
bin100101001011011…
…0001010011101001
310012221100201010021
41022112301103221
510023323424423
6323441520441
742625301002
oct11226612351
93187321107
101247483113
11590198588
122a9943121
1316b5ab0b6
14bb9701a9
15747b995d
hex4a5b14e9

1247483113 has 2 divisors, whose sum is σ = 1247483114. Its totient is φ = 1247483112.

The previous prime is 1247483063. The next prime is 1247483119. The reversal of 1247483113 is 3113847421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1237069584 + 10413529 = 35172^2 + 3227^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1247483113 is a prime.

It is a super-3 number, since 3×12474831133 (a number of 28 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1247483119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 623741556 + 623741557.

It is an arithmetic number, because the mean of its divisors is an integer number (623741557).

Almost surely, 21247483113 is an apocalyptic number.

It is an amenable number.

1247483113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1247483113 is an equidigital number, since it uses as much as digits as its factorization.

1247483113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16128, while the sum is 34.

The square root of 1247483113 is about 35319.7269666684. The cubic root of 1247483113 is about 1076.4938633976.

The spelling of 1247483113 in words is "one billion, two hundred forty-seven million, four hundred eighty-three thousand, one hundred thirteen".