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1248294248353 is a prime number
BaseRepresentation
bin10010001010100100001…
…000101001111110100001
311102100001202212010020101
4102022210020221332201
5130423001311421403
62353243005542401
7156120616016635
oct22124410517641
94370052763211
101248294248353
11441442618739
12181b17274a01
1390937b46219
14445bc4b6dc5
152270e94271d
hex122a4229fa1

1248294248353 has 2 divisors, whose sum is σ = 1248294248354. Its totient is φ = 1248294248352.

The previous prime is 1248294248329. The next prime is 1248294248359. The reversal of 1248294248353 is 3538424928421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 728320575889 + 519973672464 = 853417^2 + 721092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1248294248353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1248294248294 and 1248294248303.

It is not a weakly prime, because it can be changed into another prime (1248294248359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 624147124176 + 624147124177.

It is an arithmetic number, because the mean of its divisors is an integer number (624147124177).

Almost surely, 21248294248353 is an apocalyptic number.

It is an amenable number.

1248294248353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1248294248353 is an equidigital number, since it uses as much as digits as its factorization.

1248294248353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13271040, while the sum is 55.

The spelling of 1248294248353 in words is "one trillion, two hundred forty-eight billion, two hundred ninety-four million, two hundred forty-eight thousand, three hundred fifty-three".