Base | Representation |
---|---|
bin | 11100011010111111010100… |
… | …101010011001110100001111 |
3 | 121101120212211222222002202001 |
4 | 130122333110222121310033 |
5 | 112341000000240213241 |
6 | 1121504112513013131 |
7 | 35220644361253405 |
oct | 3432772452316417 |
9 | 541525758862661 |
10 | 125000001101071 |
11 | 36913225972a48 |
12 | 12029a075541a7 |
13 | 54995ac7b8155 |
14 | 22c2064a21475 |
15 | e6b80bee3431 |
hex | 71afd4a99d0f |
125000001101071 has 2 divisors, whose sum is σ = 125000001101072. Its totient is φ = 125000001101070.
The previous prime is 125000001101021. The next prime is 125000001101231. The reversal of 125000001101071 is 170101100000521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125000001101071 - 225 = 124999967546639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125000001101021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62500000550535 + 62500000550536.
It is an arithmetic number, because the mean of its divisors is an integer number (62500000550536).
Almost surely, 2125000001101071 is an apocalyptic number.
125000001101071 is a deficient number, since it is larger than the sum of its proper divisors (1).
125000001101071 is an equidigital number, since it uses as much as digits as its factorization.
125000001101071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 70, while the sum is 19.
Adding to 125000001101071 its reverse (170101100000521), we get a palindrome (295101101101592).
The spelling of 125000001101071 in words is "one hundred twenty-five trillion, one million, one hundred one thousand, seventy-one".
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