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1250013763093 is a prime number
BaseRepresentation
bin10010001100001010101…
…000000101011000010101
311102111111121102112000111
4102030022220011120111
5130440012010404333
62354125353043021
7156211335450304
oct22141250053025
94374447375014
101250013763093
114421451aa5a7
121823170b6471
1390b50166074
14447029dc43b
15227b089d4cd
hex1230aa05615

1250013763093 has 2 divisors, whose sum is σ = 1250013763094. Its totient is φ = 1250013763092.

The previous prime is 1250013762979. The next prime is 1250013763139. The reversal of 1250013763093 is 3903673100521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1215942879204 + 34070883889 = 1102698^2 + 184583^2 .

It is an emirp because it is prime and its reverse (3903673100521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1250013763093 - 29 = 1250013762581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1250013163093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625006881546 + 625006881547.

It is an arithmetic number, because the mean of its divisors is an integer number (625006881547).

Almost surely, 21250013763093 is an apocalyptic number.

It is an amenable number.

1250013763093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250013763093 is an equidigital number, since it uses as much as digits as its factorization.

1250013763093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 102060, while the sum is 40.

The spelling of 1250013763093 in words is "one trillion, two hundred fifty billion, thirteen million, seven hundred sixty-three thousand, ninety-three".