Base | Representation |
---|---|
bin | 11100011011000010010100… |
… | …000000011111100111011111 |
3 | 121101121012010201121011000121 |
4 | 130123002110000133213133 |
5 | 112341023034100342010 |
6 | 1121505403231335411 |
7 | 35221120051660333 |
oct | 3433022400374737 |
9 | 541535121534017 |
10 | 125003211340255 |
11 | 36914622a7a186 |
12 | 1202a562681567 |
13 | 54999a1900371 |
14 | 22c228b1137c3 |
15 | e6b948c653da |
hex | 71b09401f9df |
125003211340255 has 16 divisors (see below), whose sum is σ = 158139427932864. Its totient is φ = 94668501058560.
The previous prime is 125003211340223. The next prime is 125003211340261. The reversal of 125003211340255 is 552043112300521.
It is not a de Polignac number, because 125003211340255 - 25 = 125003211340223 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 125003211340255.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5603001456 + ... + 5603023765.
It is an arithmetic number, because the mean of its divisors is an integer number (9883714245804).
Almost surely, 2125003211340255 is an apocalyptic number.
125003211340255 is a deficient number, since it is larger than the sum of its proper divisors (33136216592609).
125003211340255 is a wasteful number, since it uses less digits than its factorization.
125003211340255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11206025346.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 125003211340255 its reverse (552043112300521), we get a palindrome (677046323640776).
The spelling of 125003211340255 in words is "one hundred twenty-five trillion, three billion, two hundred eleven million, three hundred forty thousand, two hundred fifty-five".
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