1250042531 has 2 divisors, whose sum is σ = 1250042532. Its totient is φ = 1250042530.

The previous prime is 1250042501. The next prime is 1250042533. The reversal of 1250042531 is 1352400521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1250042531 - 2¹⁸ = 1249780387 is a prime.

It is a super-2 number, since 2×1250042531² = 3125212658617771922, which contains 22 as substring.

Together with 1250042533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1250042497 and 1250042506.

It is not a weakly prime, because it can be changed into another prime (1250042533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625021265 + 625021266.

It is an arithmetic number, because the mean of its divisors is an integer number (625021266).

Almost surely, 2^1250042531 is an apocalyptic number.

1250042531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250042531 is an equidigital number, since it uses as much as digits as its factorization.

1250042531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 1250042531 is about 35355.9405333814. The cubic root of 1250042531 is about 1077.2295622456.

The spelling of 1250042531 in words is "one billion, two hundred fifty million, forty-two thousand, five hundred thirty-one".