Base | Representation |
---|---|
bin | 111010001101101011… |
… | …1001101110001010110 |
3 | 102221200101020121020121 |
4 | 1310123113031301112 |
5 | 4022011324402014 |
6 | 133232533022154 |
7 | 12013641001555 |
oct | 1643327156126 |
9 | 387611217217 |
10 | 125013122134 |
11 | 49021714a6a |
12 | 2028a78495a |
13 | ba3398b924 |
14 | 609d061d9c |
15 | 33ba150124 |
hex | 1d1b5cdc56 |
125013122134 has 8 divisors (see below), whose sum is σ = 187525617840. Its totient is φ = 62504582856.
The previous prime is 125013122111. The next prime is 125013122137. The reversal of 125013122134 is 431221310521.
125013122134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 125013122099 and 125013122108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125013122137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 908809 + ... + 1037284.
It is an arithmetic number, because the mean of its divisors is an integer number (23440702230).
Almost surely, 2125013122134 is an apocalyptic number.
125013122134 is a deficient number, since it is larger than the sum of its proper divisors (62512495706).
125013122134 is a wasteful number, since it uses less digits than its factorization.
125013122134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1978214.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 125013122134 its reverse (431221310521), we get a palindrome (556234432655).
The spelling of 125013122134 in words is "one hundred twenty-five billion, thirteen million, one hundred twenty-two thousand, one hundred thirty-four".
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