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12501316484149 is a prime number
BaseRepresentation
bin1011010111101011000010…
…0001110011110000110101
31122021010002020111010210011
42311322300201303300311
53114310144004443044
642331005302100221
72430122163556153
oct265726041636065
948233066433704
1012501316484149
113a8a862279329
12149aa0971a671
136c8b3b4c765c
143130d19b43d3
1516a2c43ed134
hexb5eb0873c35

12501316484149 has 2 divisors, whose sum is σ = 12501316484150. Its totient is φ = 12501316484148.

The previous prime is 12501316484141. The next prime is 12501316484201. The reversal of 12501316484149 is 94148461310521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11534276326225 + 967040157924 = 3396215^2 + 983382^2 .

It is a cyclic number.

It is not a de Polignac number, because 12501316484149 - 23 = 12501316484141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12501316484141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250658242074 + 6250658242075.

It is an arithmetic number, because the mean of its divisors is an integer number (6250658242075).

Almost surely, 212501316484149 is an apocalyptic number.

It is an amenable number.

12501316484149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12501316484149 is an equidigital number, since it uses as much as digits as its factorization.

12501316484149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 829440, while the sum is 49.

The spelling of 12501316484149 in words is "twelve trillion, five hundred one billion, three hundred sixteen million, four hundred eighty-four thousand, one hundred forty-nine".