125020127 has 2 divisors, whose sum is σ = 125020128. Its totient is φ = 125020126.

The previous prime is 125020109. The next prime is 125020177. The reversal of 125020127 is 721020521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 125020127 - 2¹⁴ = 125003743 is a prime.

It is a super-2 number, since 2×125020127² = 31260064310192258, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125020099 and 125020108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125020177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62510063 + 62510064.

It is an arithmetic number, because the mean of its divisors is an integer number (62510064).

Almost surely, 2^125020127 is an apocalyptic number.

125020127 is a deficient number, since it is larger than the sum of its proper divisors (1).

125020127 is an equidigital number, since it uses as much as digits as its factorization.

125020127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 20.

The square root of 125020127 is about 11181.2399580726. The cubic root of 125020127 is about 500.0268345598.

Adding to 125020127 its reverse (721020521), we get a palindrome (846040648).

The spelling of 125020127 in words is "one hundred twenty-five million, twenty thousand, one hundred twenty-seven".