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125021343437 is a prime number
BaseRepresentation
bin111010001101111011…
…0100100111011001101
3102221200221201021202022
41310123312210323031
54022020430442222
6133233425135525
712014100612434
oct1643366447315
9387627637668
10125021343437
114902631a831
122029148a5a5
13ba355a99c3
1460a01a211b
1533bac26042
hex1d1bda4ecd

125021343437 has 2 divisors, whose sum is σ = 125021343438. Its totient is φ = 125021343436.

The previous prime is 125021343389. The next prime is 125021343529. The reversal of 125021343437 is 734343120521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123917376361 + 1103967076 = 352019^2 + 33226^2 .

It is an emirp because it is prime and its reverse (734343120521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125021343437 - 234 = 107841474253 is a prime.

It is a super-3 number, since 3×1250213434373 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125021343397 and 125021343406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125021393437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62510671718 + 62510671719.

It is an arithmetic number, because the mean of its divisors is an integer number (62510671719).

Almost surely, 2125021343437 is an apocalyptic number.

It is an amenable number.

125021343437 is a deficient number, since it is larger than the sum of its proper divisors (1).

125021343437 is an equidigital number, since it uses as much as digits as its factorization.

125021343437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 125021343437 its reverse (734343120521), we get a palindrome (859364463958).

The spelling of 125021343437 in words is "one hundred twenty-five billion, twenty-one million, three hundred forty-three thousand, four hundred thirty-seven".