12502198129 has 2 divisors, whose sum is σ = 12502198130. Its totient is φ = 12502198128.

The previous prime is 12502198127. The next prime is 12502198153. The reversal of 12502198129 is 92189120521.

12502198129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12050550625 + 451647504 = 109775^2 + 21252^2 .

It is an emirp because it is prime and its reverse (92189120521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12502198129 - 2¹ = 12502198127 is a prime.

It is a super-2 number, since 2×12502198129² (a number of 21 digits) contains 22 as substring.

Together with 12502198127, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12502198091 and 12502198100.

It is not a weakly prime, because it can be changed into another prime (12502198127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6251099064 + 6251099065.

It is an arithmetic number, because the mean of its divisors is an integer number (6251099065).

Almost surely, 2^12502198129 is an apocalyptic number.

It is an amenable number.

12502198129 is a deficient number, since it is larger than the sum of its proper divisors (1).

12502198129 is an equidigital number, since it uses as much as digits as its factorization.

12502198129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 40.

The spelling of 12502198129 in words is "twelve billion, five hundred two million, one hundred ninety-eight thousand, one hundred twenty-nine".