Base | Representation |
---|---|
bin | 1011010111101111001010… |
… | …0110011101100110010101 |
3 | 1122021012221111100121010102 |
4 | 2311323302212131212111 |
5 | 3114314431300002331 |
6 | 42331311301303445 |
7 | 2430161514031613 |
oct | 265736246354625 |
9 | 48235844317112 |
10 | 12502425000341 |
11 | 3a90280a7aa11 |
12 | 149b078a04b85 |
13 | 6c8c8706a6b3 |
14 | 313198ccc6b3 |
15 | 16a33b8b74cb |
hex | b5ef299d995 |
12502425000341 has 32 divisors (see below), whose sum is σ = 13767452160000. Its totient is φ = 11300722760448.
The previous prime is 12502425000323. The next prime is 12502425000347. The reversal of 12502425000341 is 14300052420521.
It is a cyclic number.
It is not a de Polignac number, because 12502425000341 - 222 = 12502420806037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12502425000347) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1189229501 + ... + 1189240013.
It is an arithmetic number, because the mean of its divisors is an integer number (430232880000).
Almost surely, 212502425000341 is an apocalyptic number.
It is an amenable number.
12502425000341 is a deficient number, since it is larger than the sum of its proper divisors (1265027159659).
12502425000341 is a wasteful number, since it uses less digits than its factorization.
12502425000341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17193.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 12502425000341 its reverse (14300052420521), we get a palindrome (26802477420862).
The spelling of 12502425000341 in words is "twelve trillion, five hundred two billion, four hundred twenty-five million, three hundred forty-one", and thus it is an aban number.
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