Base | Representation |
---|---|
bin | 11100011011011011011111… |
… | …110001101110001111000011 |
3 | 121101200202221021000021100201 |
4 | 130123123133301232033003 |
5 | 112341443424044341123 |
6 | 1121530034402030031 |
7 | 35223065131454632 |
oct | 3433333761561703 |
9 | 541622837007321 |
10 | 125030252340163 |
11 | 36925039a06695 |
12 | 1203384a648317 |
13 | 549c3c0c37921 |
14 | 22c36d4589519 |
15 | e6c4ccbe85ad |
hex | 71b6dfc6e3c3 |
125030252340163 has 2 divisors, whose sum is σ = 125030252340164. Its totient is φ = 125030252340162.
The previous prime is 125030252340143. The next prime is 125030252340193. The reversal of 125030252340163 is 361043252030521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125030252340163 - 29 = 125030252339651 is a prime.
It is not a weakly prime, because it can be changed into another prime (125030252340143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62515126170081 + 62515126170082.
It is an arithmetic number, because the mean of its divisors is an integer number (62515126170082).
Almost surely, 2125030252340163 is an apocalyptic number.
125030252340163 is a deficient number, since it is larger than the sum of its proper divisors (1).
125030252340163 is an equidigital number, since it uses as much as digits as its factorization.
125030252340163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 125030252340163 in words is "one hundred twenty-five trillion, thirty billion, two hundred fifty-two million, three hundred forty thousand, one hundred sixty-three".
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