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125030252340143 is a prime number
BaseRepresentation
bin11100011011011011011111…
…110001101110001110101111
3121101200202221021000021022222
4130123123133301232032233
5112341443424044341033
61121530034402025555
735223065131454603
oct3433333761561657
9541622837007288
10125030252340143
1136925039a06677
121203384a6482bb
13549c3c0c37907
1422c36d4589503
15e6c4ccbe8598
hex71b6dfc6e3af

125030252340143 has 2 divisors, whose sum is σ = 125030252340144. Its totient is φ = 125030252340142.

The previous prime is 125030252340089. The next prime is 125030252340163. The reversal of 125030252340143 is 341043252030521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 125030252340143 - 212 = 125030252336047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125030252340163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62515126170071 + 62515126170072.

It is an arithmetic number, because the mean of its divisors is an integer number (62515126170072).

Almost surely, 2125030252340143 is an apocalyptic number.

125030252340143 is a deficient number, since it is larger than the sum of its proper divisors (1).

125030252340143 is an equidigital number, since it uses as much as digits as its factorization.

125030252340143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

The spelling of 125030252340143 in words is "one hundred twenty-five trillion, thirty billion, two hundred fifty-two million, three hundred forty thousand, one hundred forty-three".