Base | Representation |
---|---|
bin | 10010001100011100000… |
… | …001001000000001110101 |
3 | 11102112020221110022222111 |
4 | 102030130001020001311 |
5 | 130441111204241323 |
6 | 2354214334531021 |
7 | 156221510511412 |
oct | 22143401100165 |
9 | 4375227408874 |
10 | 1250305540213 |
11 | 442284978014 |
12 | 182398966a71 |
13 | 90b98745152 |
14 | 4472d671109 |
15 | 227cb2d5c0d |
hex | 1231c048075 |
1250305540213 has 2 divisors, whose sum is σ = 1250305540214. Its totient is φ = 1250305540212.
The previous prime is 1250305540207. The next prime is 1250305540217. The reversal of 1250305540213 is 3120455030521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1144305157284 + 106000382929 = 1069722^2 + 325577^2 .
It is a cyclic number.
It is not a de Polignac number, because 1250305540213 - 25 = 1250305540181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1250305540217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625152770106 + 625152770107.
It is an arithmetic number, because the mean of its divisors is an integer number (625152770107).
Almost surely, 21250305540213 is an apocalyptic number.
It is an amenable number.
1250305540213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250305540213 is an equidigital number, since it uses as much as digits as its factorization.
1250305540213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 1250305540213 in words is "one trillion, two hundred fifty billion, three hundred five million, five hundred forty thousand, two hundred thirteen".
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