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125036437 is a prime number
BaseRepresentation
bin1110111001111…
…10011110010101
322201021111202011
413130332132111
5224002131222
620223544221
73045535501
oct734763625
9281244664
10125036437
11646417a9
1235a5b071
131cb9b476
141286b301
15ae9cc77
hex773e795

125036437 has 2 divisors, whose sum is σ = 125036438. Its totient is φ = 125036436.

The previous prime is 125036413. The next prime is 125036447. The reversal of 125036437 is 734630521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122744241 + 2292196 = 11079^2 + 1514^2 .

It is an emirp because it is prime and its reverse (734630521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125036437 - 211 = 125034389 is a prime.

It is a super-2 number, since 2×1250364372 = 31268221155309938, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125036399 and 125036408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125036447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62518218 + 62518219.

It is an arithmetic number, because the mean of its divisors is an integer number (62518219).

Almost surely, 2125036437 is an apocalyptic number.

It is an amenable number.

125036437 is a deficient number, since it is larger than the sum of its proper divisors (1).

125036437 is an equidigital number, since it uses as much as digits as its factorization.

125036437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

The square root of 125036437 is about 11181.9692809451. The cubic root of 125036437 is about 500.0485779469.

Adding to 125036437 its reverse (734630521), we get a palindrome (859666958).

The spelling of 125036437 in words is "one hundred twenty-five million, thirty-six thousand, four hundred thirty-seven".