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12504134173 is a prime number
BaseRepresentation
bin10111010010100110…
…11111001000011101
31012021102201211102111
423221103133020131
5201102024243143
65424434554021
7621602246446
oct135123371035
935242654374
1012504134173
115337292093
12250b738911
13124373657b
1486896c2cd
154d2b5399d
hex2e94df21d

12504134173 has 2 divisors, whose sum is σ = 12504134174. Its totient is φ = 12504134172.

The previous prime is 12504134147. The next prime is 12504134197. The reversal of 12504134173 is 37143140521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6351771204 + 6152362969 = 79698^2 + 78437^2 .

It is a cyclic number.

It is not a de Polignac number, because 12504134173 - 217 = 12504003101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12504134113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252067086 + 6252067087.

It is an arithmetic number, because the mean of its divisors is an integer number (6252067087).

Almost surely, 212504134173 is an apocalyptic number.

It is an amenable number.

12504134173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12504134173 is an equidigital number, since it uses as much as digits as its factorization.

12504134173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 12504134173 its reverse (37143140521), we get a palindrome (49647274694).

The spelling of 12504134173 in words is "twelve billion, five hundred four million, one hundred thirty-four thousand, one hundred seventy-three".