Base | Representation |
---|---|
bin | 11100011011101001101101… |
… | …111000001110100111111100 |
3 | 121101202020100101021102101111 |
4 | 130123221231320032213330 |
5 | 112342221211423443002 |
6 | 1121541041445051404 |
7 | 35224145405544352 |
oct | 3433515570164774 |
9 | 541666311242344 |
10 | 125045521312252 |
11 | 3693056493a392 |
12 | 120367b00b6b64 |
13 | 54a0985409958 |
14 | 22c43423c77d2 |
15 | e6cac343d3d7 |
hex | 71ba6de0e9fc |
125045521312252 has 12 divisors (see below), whose sum is σ = 219449576356416. Its totient is φ = 62345642353280.
The previous prime is 125045521312237. The next prime is 125045521312279. The reversal of 125045521312252 is 252213125540521.
It is a super-3 number, since 3×1250455213122523 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44279574124 + ... + 44279576947.
It is an arithmetic number, because the mean of its divisors is an integer number (18287464696368).
Almost surely, 2125045521312252 is an apocalyptic number.
It is an amenable number.
125045521312252 is a deficient number, since it is larger than the sum of its proper divisors (94404055044164).
125045521312252 is a wasteful number, since it uses less digits than its factorization.
125045521312252 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88559151428 (or 88559151426 counting only the distinct ones).
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 125045521312252 its reverse (252213125540521), we get a palindrome (377258646852773).
The spelling of 125045521312252 in words is "one hundred twenty-five trillion, forty-five billion, five hundred twenty-one million, three hundred twelve thousand, two hundred fifty-two".
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