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125054355510143 is a prime number
BaseRepresentation
bin11100011011110001111100…
…011100000001001101111111
3121101210002011001101011122222
4130123301330130001031333
5112342342310002311033
61121545102224355555
735224610336152343
oct3433617434011577
9541702131334588
10125054355510143
1136934288585a84
1212038456775bbb
1354a1762717597
1422c493d79d623
15e6ce3dcb8598
hex71bc7c70137f

125054355510143 has 2 divisors, whose sum is σ = 125054355510144. Its totient is φ = 125054355510142.

The previous prime is 125054355510121. The next prime is 125054355510163. The reversal of 125054355510143 is 341015553450521.

It is a strong prime.

It is an emirp because it is prime and its reverse (341015553450521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125054355510143 - 220 = 125054354461567 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125054355510094 and 125054355510103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125054355510163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62527177755071 + 62527177755072.

It is an arithmetic number, because the mean of its divisors is an integer number (62527177755072).

Almost surely, 2125054355510143 is an apocalyptic number.

125054355510143 is a deficient number, since it is larger than the sum of its proper divisors (1).

125054355510143 is an equidigital number, since it uses as much as digits as its factorization.

125054355510143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900000, while the sum is 44.

The spelling of 125054355510143 in words is "one hundred twenty-five trillion, fifty-four billion, three hundred fifty-five million, five hundred ten thousand, one hundred forty-three".