Base | Representation |
---|---|
bin | 1011010111111011100100… |
… | …0110011010011100000101 |
3 | 1122021112112120211120002112 |
4 | 2311332321012122130011 |
5 | 3114343241321433043 |
6 | 42333021544350405 |
7 | 2430340162563431 |
oct | 265767106323405 |
9 | 48245476746075 |
10 | 12505755264773 |
11 | 3a9172a905971 |
12 | 149b848175405 |
13 | 6c9397cb8174 |
14 | 3133d33059c1 |
15 | 16a483e47518 |
hex | b5fb919a705 |
12505755264773 has 2 divisors, whose sum is σ = 12505755264774. Its totient is φ = 12505755264772.
The previous prime is 12505755264719. The next prime is 12505755264799. The reversal of 12505755264773 is 37746255750521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12273972716929 + 231782547844 = 3503423^2 + 481438^2 .
It is a cyclic number.
It is not a de Polignac number, because 12505755264773 - 28 = 12505755264517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12505755264073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252877632386 + 6252877632387.
It is an arithmetic number, because the mean of its divisors is an integer number (6252877632387).
Almost surely, 212505755264773 is an apocalyptic number.
It is an amenable number.
12505755264773 is a deficient number, since it is larger than the sum of its proper divisors (1).
12505755264773 is an equidigital number, since it uses as much as digits as its factorization.
12505755264773 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61740000, while the sum is 59.
The spelling of 12505755264773 in words is "twelve trillion, five hundred five billion, seven hundred fifty-five million, two hundred sixty-four thousand, seven hundred seventy-three".
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