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12505755264773 is a prime number
BaseRepresentation
bin1011010111111011100100…
…0110011010011100000101
31122021112112120211120002112
42311332321012122130011
53114343241321433043
642333021544350405
72430340162563431
oct265767106323405
948245476746075
1012505755264773
113a9172a905971
12149b848175405
136c9397cb8174
143133d33059c1
1516a483e47518
hexb5fb919a705

12505755264773 has 2 divisors, whose sum is σ = 12505755264774. Its totient is φ = 12505755264772.

The previous prime is 12505755264719. The next prime is 12505755264799. The reversal of 12505755264773 is 37746255750521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12273972716929 + 231782547844 = 3503423^2 + 481438^2 .

It is a cyclic number.

It is not a de Polignac number, because 12505755264773 - 28 = 12505755264517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12505755264073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252877632386 + 6252877632387.

It is an arithmetic number, because the mean of its divisors is an integer number (6252877632387).

Almost surely, 212505755264773 is an apocalyptic number.

It is an amenable number.

12505755264773 is a deficient number, since it is larger than the sum of its proper divisors (1).

12505755264773 is an equidigital number, since it uses as much as digits as its factorization.

12505755264773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61740000, while the sum is 59.

The spelling of 12505755264773 in words is "twelve trillion, five hundred five billion, seven hundred fifty-five million, two hundred sixty-four thousand, seven hundred seventy-three".