Base | Representation |
---|---|
bin | 1011011000000000101111… |
… | …1011110000111001001011 |
3 | 1122021200010102211111212022 |
4 | 2312000023323300321023 |
5 | 3114404113103411331 |
6 | 42333411511035055 |
7 | 2430416466151424 |
oct | 266001373607113 |
9 | 48250112744768 |
10 | 12507144982091 |
11 | 3a92283311081 |
12 | 149bb7566ba8b |
13 | 6c9559ba64c6 |
14 | 3134c5adc64b |
15 | 16a515e5a67b |
hex | b600bef0e4b |
12507144982091 has 2 divisors, whose sum is σ = 12507144982092. Its totient is φ = 12507144982090.
The previous prime is 12507144982069. The next prime is 12507144982103. The reversal of 12507144982091 is 19028944170521.
12507144982091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (19028944170521) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12507144982091 is a prime.
It is not a weakly prime, because it can be changed into another prime (12507144982991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6253572491045 + 6253572491046.
It is an arithmetic number, because the mean of its divisors is an integer number (6253572491046).
Almost surely, 212507144982091 is an apocalyptic number.
12507144982091 is a deficient number, since it is larger than the sum of its proper divisors (1).
12507144982091 is an equidigital number, since it uses as much as digits as its factorization.
12507144982091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 53.
The spelling of 12507144982091 in words is "twelve trillion, five hundred seven billion, one hundred forty-four million, nine hundred eighty-two thousand, ninety-one".
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