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12509655050933 = 97128965515989
BaseRepresentation
bin1011011000001010000110…
…0010111010101010110101
31122021220121100222012222222
42312002201202322222311
53114424233143112213
642334504534332125
72430535625324405
oct266024142725265
948256540865888
1012509655050933
113a93351171a37
1214a05561ba045
136c9869c1c941
14313683210805
1516a6114c4808
hexb60a18baab5

12509655050933 has 4 divisors (see below), whose sum is σ = 12638620567020. Its totient is φ = 12380689534848.

The previous prime is 12509655050927. The next prime is 12509655050951. The reversal of 12509655050933 is 33905055690521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8051167901764 + 4458487149169 = 2837458^2 + 2111513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12509655050933 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12509655050903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64482757898 + ... + 64482758091.

It is an arithmetic number, because the mean of its divisors is an integer number (3159655141755).

Almost surely, 212509655050933 is an apocalyptic number.

It is an amenable number.

12509655050933 is a deficient number, since it is larger than the sum of its proper divisors (128965516087).

12509655050933 is an equidigital number, since it uses as much as digits as its factorization.

12509655050933 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128965516086.

The product of its (nonzero) digits is 5467500, while the sum is 53.

The spelling of 12509655050933 in words is "twelve trillion, five hundred nine billion, six hundred fifty-five million, fifty thousand, nine hundred thirty-three".

Divisors: 1 97 128965515989 12509655050933