Base | Representation |
---|---|
bin | 1011011000001101011000… |
… | …0001110000010111001101 |
3 | 1122021222212201210020012211 |
4 | 2312003112001300113031 |
5 | 3114433034100103123 |
6 | 42335132150430421 |
7 | 2430566506414315 |
oct | 266032601602715 |
9 | 48258781706184 |
10 | 12510535550413 |
11 | 3a9376319525a |
12 | 14a0761062411 |
13 | 6c997a479354 |
14 | 313728132445 |
15 | 16a66394d40d |
hex | b60d60705cd |
12510535550413 has 2 divisors, whose sum is σ = 12510535550414. Its totient is φ = 12510535550412.
The previous prime is 12510535550399. The next prime is 12510535550437. The reversal of 12510535550413 is 31405553501521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11577972580164 + 932562970249 = 3402642^2 + 965693^2 .
It is a cyclic number.
It is not a de Polignac number, because 12510535550413 - 217 = 12510535419341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12510535550813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255267775206 + 6255267775207.
It is an arithmetic number, because the mean of its divisors is an integer number (6255267775207).
Almost surely, 212510535550413 is an apocalyptic number.
It is an amenable number.
12510535550413 is a deficient number, since it is larger than the sum of its proper divisors (1).
12510535550413 is an equidigital number, since it uses as much as digits as its factorization.
12510535550413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225000, while the sum is 40.
The spelling of 12510535550413 in words is "twelve trillion, five hundred ten billion, five hundred thirty-five million, five hundred fifty thousand, four hundred thirteen".
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