12511021543403 has 2 divisors, whose sum is σ = 12511021543404. Its totient is φ = 12511021543402.

The previous prime is 12511021543309. The next prime is 12511021543429. The reversal of 12511021543403 is 30434512011521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12511021543403 - 2⁸ = 12511021543147 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12511021543403.

It is not a weakly prime, because it can be changed into another prime (12511021543103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255510771701 + 6255510771702.

It is an arithmetic number, because the mean of its divisors is an integer number (6255510771702).

Almost surely, 2^{12511021543403} is an apocalyptic number.

12511021543403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12511021543403 is an equidigital number, since it uses as much as digits as its factorization.

12511021543403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 12511021543403 its reverse (30434512011521), we get a palindrome (42945533554924).

The spelling of 12511021543403 in words is "twelve trillion, five hundred eleven billion, twenty-one million, five hundred forty-three thousand, four hundred three".