Base | Representation |
---|---|
bin | 11100011100100111110001… |
… | …100101001100000100100011 |
3 | 121101222121100020002222020121 |
4 | 130130213301211030010203 |
5 | 112344314143242014021 |
6 | 1122031421501221111 |
7 | 35232024562256011 |
oct | 3434476145140443 |
9 | 541877306088217 |
10 | 125112155423011 |
11 | 36956849084009 |
12 | 120476a7861797 |
13 | 54a7044412563 |
14 | 22c7663d918b1 |
15 | e6e6c32d3741 |
hex | 71c9f194c123 |
125112155423011 has 2 divisors, whose sum is σ = 125112155423012. Its totient is φ = 125112155423010.
The previous prime is 125112155422993. The next prime is 125112155423041. The reversal of 125112155423011 is 110324551211521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125112155423011 - 25 = 125112155422979 is a prime.
It is a super-2 number, since 2×1251121554230112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (125112155423041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62556077711505 + 62556077711506.
It is an arithmetic number, because the mean of its divisors is an integer number (62556077711506).
Almost surely, 2125112155423011 is an apocalyptic number.
125112155423011 is a deficient number, since it is larger than the sum of its proper divisors (1).
125112155423011 is an equidigital number, since it uses as much as digits as its factorization.
125112155423011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 34.
The spelling of 125112155423011 in words is "one hundred twenty-five trillion, one hundred twelve billion, one hundred fifty-five million, four hundred twenty-three thousand, eleven".
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