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125113248000 = 283453134779
BaseRepresentation
bin111010010000101010…
…1001010100100000000
3102221221100122112010000
41310201111022210000
54022212442414000
6133250511040000
712016265026656
oct1644125124400
9387840575100
10125113248000
1149073192014
12202b8210000
13ba4b6477c0
1460ac486dd6
1533c3d2c000
hex1d2154a900

125113248000 has 1440 divisors, whose sum is σ = 518549391360. Its totient is φ = 29760307200.

The previous prime is 125113247993. The next prime is 125113248023. The reversal of 125113248000 is 842311521.

125113248000 is a `hidden beast` number, since 1 + 2 + 51 + 132 + 480 + 0 + 0 = 666.

125113248000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (1440).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 1583711961 + ... + 1583712039.

It is an arithmetic number, because the mean of its divisors is an integer number (360103744).

Almost surely, 2125113248000 is an apocalyptic number.

125113248000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 125113248000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (259274695680).

125113248000 is an abundant number, since it is smaller than the sum of its proper divisors (393436143360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125113248000 is an equidigital number, since it uses as much as digits as its factorization.

125113248000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182 (or 149 counting only the distinct ones).

The product of its (nonzero) digits is 1920, while the sum is 27.

Adding to 125113248000 its reverse (842311521), we get a palindrome (125955559521).

The spelling of 125113248000 in words is "one hundred twenty-five billion, one hundred thirteen million, two hundred forty-eight thousand".