Base | Representation |
---|---|
bin | 11100011100110000011000… |
… | …101000000011101101111011 |
3 | 121102000111012112012112122112 |
4 | 130130300120220003231323 |
5 | 112344442112001434433 |
6 | 1122035551113442535 |
7 | 35232502641410432 |
oct | 3434603050035573 |
9 | 542014175175575 |
10 | 125121400421243 |
11 | 3695a7626a2016 |
12 | 12049447a1044b |
13 | 54a7b88873705 |
14 | 22c7c9db40119 |
15 | e6ea64c57348 |
hex | 71cc18a03b7b |
125121400421243 has 2 divisors, whose sum is σ = 125121400421244. Its totient is φ = 125121400421242.
The previous prime is 125121400421207. The next prime is 125121400421273. The reversal of 125121400421243 is 342124004121521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125121400421243 - 26 = 125121400421179 is a prime.
It is not a weakly prime, because it can be changed into another prime (125121400421273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62560700210621 + 62560700210622.
It is an arithmetic number, because the mean of its divisors is an integer number (62560700210622).
Almost surely, 2125121400421243 is an apocalyptic number.
125121400421243 is a deficient number, since it is larger than the sum of its proper divisors (1).
125121400421243 is an equidigital number, since it uses as much as digits as its factorization.
125121400421243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 125121400421243 its reverse (342124004121521), we get a palindrome (467245404542764).
The spelling of 125121400421243 in words is "one hundred twenty-five trillion, one hundred twenty-one billion, four hundred million, four hundred twenty-one thousand, two hundred forty-three".
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