Base | Representation |
---|---|
bin | 10111010011100101… |
… | …11001111111010011 |
3 | 1012022000020021201221 |
4 | 23221302321333103 |
5 | 201111131330033 |
6 | 5425331305511 |
7 | 622032252463 |
oct | 135162717723 |
9 | 35260207657 |
10 | 12512370643 |
11 | 53409a8293 |
12 | 251244b297 |
13 | 124535b516 |
14 | 869ab3ba3 |
15 | 4d372e12d |
hex | 2e9cb9fd3 |
12512370643 has 2 divisors, whose sum is σ = 12512370644. Its totient is φ = 12512370642.
The previous prime is 12512370631. The next prime is 12512370649. The reversal of 12512370643 is 34607321521.
It is a strong prime.
It is an emirp because it is prime and its reverse (34607321521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12512370643 - 233 = 3922436051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12512370599 and 12512370608.
It is not a weakly prime, because it can be changed into another prime (12512370649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256185321 + 6256185322.
It is an arithmetic number, because the mean of its divisors is an integer number (6256185322).
Almost surely, 212512370643 is an apocalyptic number.
12512370643 is a deficient number, since it is larger than the sum of its proper divisors (1).
12512370643 is an equidigital number, since it uses as much as digits as its factorization.
12512370643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 34.
The spelling of 12512370643 in words is "twelve billion, five hundred twelve million, three hundred seventy thousand, six hundred forty-three".
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