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1251263776253 is a prime number
BaseRepresentation
bin10010001101010101001…
…000100000010111111101
311102121201201112202201012
4102031111020200113331
5131000042011320003
62354453405125005
7156254324416451
oct22152510402775
94377651482635
101251263776253
11442726865a27
12182605859765
1390cbc11b91a
14447c0a2a661
15228354b78d8
hex123552205fd

1251263776253 has 2 divisors, whose sum is σ = 1251263776254. Its totient is φ = 1251263776252.

The previous prime is 1251263776207. The next prime is 1251263776277. The reversal of 1251263776253 is 3526773621521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1023927443449 + 227336332804 = 1011893^2 + 476798^2 .

It is a cyclic number.

It is not a de Polignac number, because 1251263776253 - 28 = 1251263775997 is a prime.

It is a super-2 number, since 2×12512637762532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1251263776283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625631888126 + 625631888127.

It is an arithmetic number, because the mean of its divisors is an integer number (625631888127).

Almost surely, 21251263776253 is an apocalyptic number.

It is an amenable number.

1251263776253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251263776253 is an equidigital number, since it uses as much as digits as its factorization.

1251263776253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3175200, while the sum is 50.

The spelling of 1251263776253 in words is "one trillion, two hundred fifty-one billion, two hundred sixty-three million, seven hundred seventy-six thousand, two hundred fifty-three".