1251303843343 has 2 divisors, whose sum is σ = 1251303843344. Its totient is φ = 1251303843342.

The previous prime is 1251303843311. The next prime is 1251303843371. The reversal of 1251303843343 is 3433483031521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1251303843343 - 2⁵ = 1251303843311 is a prime.

It is a super-2 number, since 2×1251303843343² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1251303843296 and 1251303843305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1251303840343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625651921671 + 625651921672.

It is an arithmetic number, because the mean of its divisors is an integer number (625651921672).

Almost surely, 2^{1251303843343} is an apocalyptic number.

1251303843343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251303843343 is an equidigital number, since it uses as much as digits as its factorization.

1251303843343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 1251303843343 its reverse (3433483031521), we get a palindrome (4684786874864).

The spelling of 1251303843343 in words is "one trillion, two hundred fifty-one billion, three hundred three million, eight hundred forty-three thousand, three hundred forty-three".