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12513164401 is a prime number
BaseRepresentation
bin10111010011101011…
…11011110001110001
31012022001201121120101
423221311323301301
5201111332230101
65425400312401
7622042066603
oct135165736161
935261647511
1012513164401
11534139a691
122512772701
1312455788ba
14869c3d173
154d3839401
hex2e9d7bc71

12513164401 has 2 divisors, whose sum is σ = 12513164402. Its totient is φ = 12513164400.

The previous prime is 12513164341. The next prime is 12513164429. The reversal of 12513164401 is 10446131521.

It is an a-pointer prime, because the next prime (12513164429) can be obtained adding 12513164401 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12392142400 + 121022001 = 111320^2 + 11001^2 .

It is a cyclic number.

It is not a de Polignac number, because 12513164401 - 217 = 12513033329 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12513164401.

It is not a weakly prime, because it can be changed into another prime (12513164431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256582200 + 6256582201.

It is an arithmetic number, because the mean of its divisors is an integer number (6256582201).

Almost surely, 212513164401 is an apocalyptic number.

It is an amenable number.

12513164401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513164401 is an equidigital number, since it uses as much as digits as its factorization.

12513164401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 12513164401 its reverse (10446131521), we get a palindrome (22959295922).

The spelling of 12513164401 in words is "twelve billion, five hundred thirteen million, one hundred sixty-four thousand, four hundred one".