Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000010010000111111 |
3 | 1122022020220212101110012012 |
4 | 2312011320221002100333 |
5 | 3120004131010200401 |
6 | 42340303005401435 |
7 | 2431024224654431 |
oct | 266057051022077 |
9 | 48266825343165 |
10 | 12513263756351 |
11 | 3a94933196806 |
12 | 14a11a286927b |
13 | 6c9cc375a2a7 |
14 | 3139065c8651 |
15 | 16a7732058bb |
hex | b6178a4243f |
12513263756351 has 2 divisors, whose sum is σ = 12513263756352. Its totient is φ = 12513263756350.
The previous prime is 12513263756341. The next prime is 12513263756359. The reversal of 12513263756351 is 15365736231521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12513263756351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12513263756351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12513263756359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631878175 + 6256631878176.
It is an arithmetic number, because the mean of its divisors is an integer number (6256631878176).
Almost surely, 212513263756351 is an apocalyptic number.
12513263756351 is a deficient number, since it is larger than the sum of its proper divisors (1).
12513263756351 is an equidigital number, since it uses as much as digits as its factorization.
12513263756351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3402000, while the sum is 50.
Adding to 12513263756351 its reverse (15365736231521), we get a palindrome (27878999987872).
The spelling of 12513263756351 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, three hundred fifty-one".
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