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12514013 is a prime number
BaseRepresentation
bin101111101111…
…001011011101
3212112202222222
4233233023131
511200422023
61124115125
7211240001
oct57571335
925482888
1012514013
117077a66
124235aa5
132791c55
14193a701
151172cc8
hexbef2dd

12514013 has 2 divisors, whose sum is σ = 12514014. Its totient is φ = 12514012.

The previous prime is 12514009. The next prime is 12514039. The reversal of 12514013 is 31041521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6744409 + 5769604 = 2597^2 + 2402^2 .

It is a cyclic number.

It is not a de Polignac number, because 12514013 - 22 = 12514009 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12513982 and 12514000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12514003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6257006 + 6257007.

It is an arithmetic number, because the mean of its divisors is an integer number (6257007).

Almost surely, 212514013 is an apocalyptic number.

It is an amenable number.

12514013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12514013 is an equidigital number, since it uses as much as digits as its factorization.

12514013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 12514013 is about 3537.5150883070. The cubic root of 12514013 is about 232.1661327398.

Adding to 12514013 its reverse (31041521), we get a palindrome (43555534).

The spelling of 12514013 in words is "twelve million, five hundred fourteen thousand, thirteen".