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1251425432099 is a prime number
BaseRepresentation
bin10010001101011110110…
…001001011001000100011
311102122010222201201211202
4102031132301023020203
5131000404402311344
62354521422031415
7156261326443343
oct22153661131043
94378128651752
101251425432099
114427aa0393a7
1218264ba1856b
139101676bc7b
14447d82aad23
152284479a94e
hex1235ec4b223

1251425432099 has 2 divisors, whose sum is σ = 1251425432100. Its totient is φ = 1251425432098.

The previous prime is 1251425432069. The next prime is 1251425432111. The reversal of 1251425432099 is 9902345241521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1251425432099 - 28 = 1251425431843 is a prime.

It is a super-3 number, since 3×12514254320993 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1251425432069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625712716049 + 625712716050.

It is an arithmetic number, because the mean of its divisors is an integer number (625712716050).

Almost surely, 21251425432099 is an apocalyptic number.

1251425432099 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251425432099 is an equidigital number, since it uses as much as digits as its factorization.

1251425432099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 47.

The spelling of 1251425432099 in words is "one trillion, two hundred fifty-one billion, four hundred twenty-five million, four hundred thirty-two thousand, ninety-nine".